A particle after starting from rest, experiences constant acceleration for 20 sec. If it covers a distance s 1 in first 10 sec, then the distance covered during next 10 sec will be
Text Solution
Verified by ExpertsThe correct answer is:
C
In 20 seconds, total distance travelled
s = 
a (20) 2 = 
a × 400
= 200 a
In first 10 seconds, the distance s 1 travelled
s 1 = 
a × (10)2
= 50a
So, in other 10 seconds, the distance s 2 travelled
s 2 = s – s 1
or s 2 = 200a – 50a or = 150a or = 3 × (50a)
Hence s 2 = 3s 1
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